Optimal. Leaf size=401 \[ -\frac{2 \left (a^2-b^2\right ) \sin ^3(c+d x) \cos (c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}+\frac{2 \left (80 a^2-63 b^2\right ) \sin ^2(c+d x) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{63 a b^3 d}-\frac{16 \left (60 a^2-49 b^2\right ) \sin (c+d x) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{315 b^4 d}+\frac{8 a \left (160 a^2-139 b^2\right ) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{315 b^5 d}-\frac{16 a \left (-199 a^2 b^2+160 a^4+39 b^4\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} F\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{315 b^6 d \sqrt{a+b \sin (c+d x)}}+\frac{8 \left (-318 a^2 b^2+320 a^4+21 b^4\right ) \sqrt{a+b \sin (c+d x)} E\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{315 b^6 d \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}-\frac{2 \sin ^3(c+d x) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{9 b^2 d} \]
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Rubi [A] time = 0.903799, antiderivative size = 401, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.258, Rules used = {2892, 3049, 3023, 2752, 2663, 2661, 2655, 2653} \[ -\frac{2 \left (a^2-b^2\right ) \sin ^3(c+d x) \cos (c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}+\frac{2 \left (80 a^2-63 b^2\right ) \sin ^2(c+d x) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{63 a b^3 d}-\frac{16 \left (60 a^2-49 b^2\right ) \sin (c+d x) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{315 b^4 d}+\frac{8 a \left (160 a^2-139 b^2\right ) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{315 b^5 d}-\frac{16 a \left (-199 a^2 b^2+160 a^4+39 b^4\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} F\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{315 b^6 d \sqrt{a+b \sin (c+d x)}}+\frac{8 \left (-318 a^2 b^2+320 a^4+21 b^4\right ) \sqrt{a+b \sin (c+d x)} E\left (\frac{1}{2} \left (c+d x-\frac{\pi }{2}\right )|\frac{2 b}{a+b}\right )}{315 b^6 d \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}-\frac{2 \sin ^3(c+d x) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{9 b^2 d} \]
Antiderivative was successfully verified.
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Rule 2892
Rule 3049
Rule 3023
Rule 2752
Rule 2663
Rule 2661
Rule 2655
Rule 2653
Rubi steps
\begin{align*} \int \frac{\cos ^4(c+d x) \sin ^2(c+d x)}{(a+b \sin (c+d x))^{3/2}} \, dx &=-\frac{2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}-\frac{2 \cos (c+d x) \sin ^3(c+d x) \sqrt{a+b \sin (c+d x)}}{9 b^2 d}+\frac{4 \int \frac{\sin ^2(c+d x) \left (\frac{15}{4} \left (4 a^2-3 b^2\right )-\frac{1}{2} a b \sin (c+d x)-\frac{1}{4} \left (80 a^2-63 b^2\right ) \sin ^2(c+d x)\right )}{\sqrt{a+b \sin (c+d x)}} \, dx}{9 a b^2}\\ &=-\frac{2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}+\frac{2 \left (80 a^2-63 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt{a+b \sin (c+d x)}}{63 a b^3 d}-\frac{2 \cos (c+d x) \sin ^3(c+d x) \sqrt{a+b \sin (c+d x)}}{9 b^2 d}+\frac{8 \int \frac{\sin (c+d x) \left (-\frac{1}{2} a \left (80 a^2-63 b^2\right )+\frac{5}{2} a^2 b \sin (c+d x)+a \left (60 a^2-49 b^2\right ) \sin ^2(c+d x)\right )}{\sqrt{a+b \sin (c+d x)}} \, dx}{63 a b^3}\\ &=-\frac{2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}-\frac{16 \left (60 a^2-49 b^2\right ) \cos (c+d x) \sin (c+d x) \sqrt{a+b \sin (c+d x)}}{315 b^4 d}+\frac{2 \left (80 a^2-63 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt{a+b \sin (c+d x)}}{63 a b^3 d}-\frac{2 \cos (c+d x) \sin ^3(c+d x) \sqrt{a+b \sin (c+d x)}}{9 b^2 d}+\frac{16 \int \frac{a^2 \left (60 a^2-49 b^2\right )-\frac{1}{4} a b \left (40 a^2-21 b^2\right ) \sin (c+d x)-\frac{3}{4} a^2 \left (160 a^2-139 b^2\right ) \sin ^2(c+d x)}{\sqrt{a+b \sin (c+d x)}} \, dx}{315 a b^4}\\ &=-\frac{2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}+\frac{8 a \left (160 a^2-139 b^2\right ) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{315 b^5 d}-\frac{16 \left (60 a^2-49 b^2\right ) \cos (c+d x) \sin (c+d x) \sqrt{a+b \sin (c+d x)}}{315 b^4 d}+\frac{2 \left (80 a^2-63 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt{a+b \sin (c+d x)}}{63 a b^3 d}-\frac{2 \cos (c+d x) \sin ^3(c+d x) \sqrt{a+b \sin (c+d x)}}{9 b^2 d}+\frac{32 \int \frac{\frac{3}{8} a^2 b \left (80 a^2-57 b^2\right )+\frac{3}{8} a \left (320 a^4-318 a^2 b^2+21 b^4\right ) \sin (c+d x)}{\sqrt{a+b \sin (c+d x)}} \, dx}{945 a b^5}\\ &=-\frac{2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}+\frac{8 a \left (160 a^2-139 b^2\right ) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{315 b^5 d}-\frac{16 \left (60 a^2-49 b^2\right ) \cos (c+d x) \sin (c+d x) \sqrt{a+b \sin (c+d x)}}{315 b^4 d}+\frac{2 \left (80 a^2-63 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt{a+b \sin (c+d x)}}{63 a b^3 d}-\frac{2 \cos (c+d x) \sin ^3(c+d x) \sqrt{a+b \sin (c+d x)}}{9 b^2 d}+\frac{\left (4 \left (320 a^4-318 a^2 b^2+21 b^4\right )\right ) \int \sqrt{a+b \sin (c+d x)} \, dx}{315 b^6}-\frac{\left (8 a \left (160 a^4-199 a^2 b^2+39 b^4\right )\right ) \int \frac{1}{\sqrt{a+b \sin (c+d x)}} \, dx}{315 b^6}\\ &=-\frac{2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}+\frac{8 a \left (160 a^2-139 b^2\right ) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{315 b^5 d}-\frac{16 \left (60 a^2-49 b^2\right ) \cos (c+d x) \sin (c+d x) \sqrt{a+b \sin (c+d x)}}{315 b^4 d}+\frac{2 \left (80 a^2-63 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt{a+b \sin (c+d x)}}{63 a b^3 d}-\frac{2 \cos (c+d x) \sin ^3(c+d x) \sqrt{a+b \sin (c+d x)}}{9 b^2 d}+\frac{\left (4 \left (320 a^4-318 a^2 b^2+21 b^4\right ) \sqrt{a+b \sin (c+d x)}\right ) \int \sqrt{\frac{a}{a+b}+\frac{b \sin (c+d x)}{a+b}} \, dx}{315 b^6 \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}-\frac{\left (8 a \left (160 a^4-199 a^2 b^2+39 b^4\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}}\right ) \int \frac{1}{\sqrt{\frac{a}{a+b}+\frac{b \sin (c+d x)}{a+b}}} \, dx}{315 b^6 \sqrt{a+b \sin (c+d x)}}\\ &=-\frac{2 \left (a^2-b^2\right ) \cos (c+d x) \sin ^3(c+d x)}{a b^2 d \sqrt{a+b \sin (c+d x)}}+\frac{8 a \left (160 a^2-139 b^2\right ) \cos (c+d x) \sqrt{a+b \sin (c+d x)}}{315 b^5 d}-\frac{16 \left (60 a^2-49 b^2\right ) \cos (c+d x) \sin (c+d x) \sqrt{a+b \sin (c+d x)}}{315 b^4 d}+\frac{2 \left (80 a^2-63 b^2\right ) \cos (c+d x) \sin ^2(c+d x) \sqrt{a+b \sin (c+d x)}}{63 a b^3 d}-\frac{2 \cos (c+d x) \sin ^3(c+d x) \sqrt{a+b \sin (c+d x)}}{9 b^2 d}+\frac{8 \left (320 a^4-318 a^2 b^2+21 b^4\right ) E\left (\frac{1}{2} \left (c-\frac{\pi }{2}+d x\right )|\frac{2 b}{a+b}\right ) \sqrt{a+b \sin (c+d x)}}{315 b^6 d \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}-\frac{16 a \left (160 a^4-199 a^2 b^2+39 b^4\right ) F\left (\frac{1}{2} \left (c-\frac{\pi }{2}+d x\right )|\frac{2 b}{a+b}\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}}}{315 b^6 d \sqrt{a+b \sin (c+d x)}}\\ \end{align*}
Mathematica [A] time = 5.06707, size = 275, normalized size = 0.69 \[ \frac{-b \cos (c+d x) \left (-8 \left (40 a^2 b^2-21 b^4\right ) \cos (2 (c+d x))+4768 a^2 b^2-1280 a^3 b \sin (c+d x)-5120 a^4+1012 a b^3 \sin (c+d x)+100 a b^3 \sin (3 (c+d x))+35 b^4 \cos (4 (c+d x))-203 b^4\right )+64 a \left (-199 a^2 b^2+160 a^4+39 b^4\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} F\left (\frac{1}{4} (-2 c-2 d x+\pi )|\frac{2 b}{a+b}\right )-32 \left (-318 a^3 b^2-318 a^2 b^3+320 a^4 b+320 a^5+21 a b^4+21 b^5\right ) \sqrt{\frac{a+b \sin (c+d x)}{a+b}} E\left (\frac{1}{4} (-2 c-2 d x+\pi )|\frac{2 b}{a+b}\right )}{1260 b^6 d \sqrt{a+b \sin (c+d x)}} \]
Antiderivative was successfully verified.
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Maple [B] time = 1.694, size = 1190, normalized size = 3. \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cos \left (d x + c\right )^{4} \sin \left (d x + c\right )^{2}}{{\left (b \sin \left (d x + c\right ) + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (\cos \left (d x + c\right )^{6} - \cos \left (d x + c\right )^{4}\right )} \sqrt{b \sin \left (d x + c\right ) + a}}{b^{2} \cos \left (d x + c\right )^{2} - 2 \, a b \sin \left (d x + c\right ) - a^{2} - b^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\cos \left (d x + c\right )^{4} \sin \left (d x + c\right )^{2}}{{\left (b \sin \left (d x + c\right ) + a\right )}^{\frac{3}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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